What are the solutions to the equation x^2+20x+101=0 ?

The solutions to the equation x^2+20x+101=0 are x=-10+i,x=-10-i

Find the zeros of x^2+20x+101=0

The zeros of x^2+20x+101=0 are x=-10+i,x=-10-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 20 x + 101 = 0

x = - 10 + i, x = - 10 - i

Solution steps

x^{2} + 20 x + 101 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 101}{2 \cdot 1}

Simplify

2 0^{2} - 4 \cdot 1 \cdot 101 : 2 i

x_{1, 2} = \frac{- 20 \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 2 i}{2 \cdot 1}, x_{2} = \frac{- 20 - 2 i}{2 \cdot 1}

x = \frac{- 20 + 2 i}{2 \cdot 1} : - 10 + i

x = \frac{- 20 - 2 i}{2 \cdot 1} : - 10 - i

The solutions to the quadratic equation are:

x = - 10 + i, x = - 10 - i

x^{2} + 118 = 20 x

a x^{2} + b x + c

x^{2} + 10 x = - 16

x, x^{2} + y^{2} + z^{2} = 25

m x^{2} - n x + 1 = 0

What are the solutions to the equation x^2+20x+101=0 ?
The solutions to the equation x^2+20x+101=0 are x=-10+i,x=-10-i
Find the zeros of x^2+20x+101=0
The zeros of x^2+20x+101=0 are x=-10+i,x=-10-i