What are the solutions to the equation 3x^2+30=-18x ?

The solutions to the equation 3x^2+30=-18x are x=-3+i,x=-3-i

Find the zeros of 3x^2+30=-18x

The zeros of 3x^2+30=-18x are x=-3+i,x=-3-i

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3 x^{2} + 30 = - 18 x

x = - 3 + i, x = - 3 - i

Solution steps

3 x^{2} + 30 = - 18 x

Move

18 x

to the left side

3 x^{2} + 30 + 18 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 18 x + 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 3 \cdot 30}{2 \cdot 3}

Simplify

1 8^{2} - 4 \cdot 3 \cdot 30 : 6 i

x_{1, 2} = \frac{- 18 \pm 6 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 18 + 6 i}{2 \cdot 3}, x_{2} = \frac{- 18 - 6 i}{2 \cdot 3}

x = \frac{- 18 + 6 i}{2 \cdot 3} : - 3 + i

x = \frac{- 18 - 6 i}{2 \cdot 3} : - 3 - i

The solutions to the quadratic equation are:

x = - 3 + i, x = - 3 - i

5 x^{2} + 17 x + 6 = 0

3 x^{2} = 2 (2 x + 1)

3 x - 6 x^{2} = 2 x^{2} - 5 x

x^{2} + 6 x + 3

x^{2} - 3 x - 11 = 0

What are the solutions to the equation 3x^2+30=-18x ?
The solutions to the equation 3x^2+30=-18x are x=-3+i,x=-3-i
Find the zeros of 3x^2+30=-18x
The zeros of 3x^2+30=-18x are x=-3+i,x=-3-i