What are the solutions to the equation 4(x+9)^2+8=32 ?

The solutions to the equation 4(x+9)^2+8=32 are x=sqrt(6)-9,x=-sqrt(6)-9

Find the zeros of 4(x+9)^2+8=32

The zeros of 4(x+9)^2+8=32 are x=sqrt(6)-9,x=-sqrt(6)-9

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4 (x + 9)^{2} + 8 = 32

x = 6 - 9, x = - 6 - 9

Decimal Notation

x = - 6.55051 \dots, x = - 11.44948 \dots

Solution steps

4 (x + 9)^{2} + 8 = 32

Move

8

to the right side

4 (x + 9)^{2} = 24

Divide both sides by

4

(x + 9)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 9 = 6 : x = 6 - 9

Solve

x + 9 = - 6 : x = - 6 - 9

The solutions to the quadratic equation are:

x = 6 - 9, x = - 6 - 9

(x - 1) (x - 5) = - 3

3 x^{2} + 48 x = - 204

x^{2} - 4 x - 15 = 0

5 x^{2} - 10 x - 13 = 9 x - 9

r, A = 2 π r^{2} + 2 π r h

What are the solutions to the equation 4(x+9)^2+8=32 ?
The solutions to the equation 4(x+9)^2+8=32 are x=sqrt(6)-9,x=-sqrt(6)-9
Find the zeros of 4(x+9)^2+8=32
The zeros of 4(x+9)^2+8=32 are x=sqrt(6)-9,x=-sqrt(6)-9