What are the solutions to the equation y(y+4)=-4 ?

The solutions to the equation y(y+4)=-4 are y=-2

Find the zeros of y(y+4)=-4

The zeros of y(y+4)=-4 are y=-2

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y (y + 4) = - 4

y = - 2

Solution steps

y (y + 4) = - 4

Expand

y (y + 4) : y^{2} + 4 y

y^{2} + 4 y = - 4

Move

4

to the left side

y^{2} + 4 y + 4 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

y_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

y = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

y = - 2

The solution to the quadratic equation is:

y = - 2

4 x^{2} - 4 x - 8 = 0

x, f = x^{2} + y^{2} + z^{2}

- 2 x^{2} + 2 x - 3 = 0

- 36 + (x - 12)^{2} = 24

a, a^{2} = b^{2}

What are the solutions to the equation y(y+4)=-4 ?
The solutions to the equation y(y+4)=-4 are y=-2
Find the zeros of y(y+4)=-4
The zeros of y(y+4)=-4 are y=-2