What are the solutions to the equation solvefor c,x^2+y^2=c^2 ?

The solutions to the equation solvefor c,x^2+y^2=c^2 are c=sqrt(x^2+y^2),c=-sqrt(x^2+y^2)

Find the zeros of solvefor c,x^2+y^2=c^2

The zeros of solvefor c,x^2+y^2=c^2 are c=sqrt(x^2+y^2),c=-sqrt(x^2+y^2)

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solve for

c, x^{2} + y^{2} = c^{2}

c = x^{2} + y^{2}, c = - x^{2} + y^{2}

Solution steps

x^{2} + y^{2} = c^{2}

Switch sides

c^{2} = x^{2} + y^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = x^{2} + y^{2}, c = - x^{2} + y^{2}

2 x^{2} - 4 = 16 x

- 7 x^{2} - 2 = - 10 x

x^{2} - 18 x

3 p^{2} + 9 p = - 6

2 (x^{2} + 2) - 6 = 6

What are the solutions to the equation solvefor c,x^2+y^2=c^2 ?
The solutions to the equation solvefor c,x^2+y^2=c^2 are c=sqrt(x^2+y^2),c=-sqrt(x^2+y^2)
Find the zeros of solvefor c,x^2+y^2=c^2
The zeros of solvefor c,x^2+y^2=c^2 are c=sqrt(x^2+y^2),c=-sqrt(x^2+y^2)