What are the solutions to the equation 25x^2-40x+17=0 ?

The solutions to the equation 25x^2-40x+17=0 are x= 4/5+i 1/5 ,x= 4/5-i 1/5

Find the zeros of 25x^2-40x+17=0

The zeros of 25x^2-40x+17=0 are x= 4/5+i 1/5 ,x= 4/5-i 1/5

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25 x^{2} - 40 x + 17 = 0

x = \frac{4}{5} + i \frac{1}{5}, x = \frac{4}{5} - i \frac{1}{5}

Solution steps

25 x^{2} - 40 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 25 \cdot 17}{2 \cdot 25}

Simplify

(- 40)^{2} - 4 \cdot 25 \cdot 17 : 10 i

x_{1, 2} = \frac{- ( - 40 ) \pm 10 i}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 10 i}{2 \cdot 25}, x_{2} = \frac{- ( - 40 ) - 10 i}{2 \cdot 25}

x = \frac{- ( - 40 ) + 10 i}{2 \cdot 25} : \frac{4}{5} + i \frac{1}{5}

x = \frac{- ( - 40 ) - 10 i}{2 \cdot 25} : \frac{4}{5} - i \frac{1}{5}

The solutions to the quadratic equation are:

x = \frac{4}{5} + i \frac{1}{5}, x = \frac{4}{5} - i \frac{1}{5}

a^{2} - 2 a + 1 = 3

x^{2} = 6 x + 1

3 x^{2} - 27 x - 18 = 0

2 x^{2} + 4 x + 1

- 4 x^{2} + 4 x - 1 = 0

What are the solutions to the equation 25x^2-40x+17=0 ?
The solutions to the equation 25x^2-40x+17=0 are x= 4/5+i 1/5 ,x= 4/5-i 1/5
Find the zeros of 25x^2-40x+17=0
The zeros of 25x^2-40x+17=0 are x= 4/5+i 1/5 ,x= 4/5-i 1/5