What are the solutions to the equation 2x^2-20x=x^2-19 ?

The solutions to the equation 2x^2-20x=x^2-19 are x=19,x=1

Find the zeros of 2x^2-20x=x^2-19

The zeros of 2x^2-20x=x^2-19 are x=19,x=1

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2 x^{2} - 20 x = x^{2} - 19

x = 19, x = 1

Solution steps

2 x^{2} - 20 x = x^{2} - 19

Move

19

to the left side

2 x^{2} - 20 x + 19 = x^{2}

Move

x^{2}

to the left side

x^{2} - 20 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 19}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot 19 = 18

x_{1, 2} = \frac{- ( - 20 ) \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 18}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 18}{2 \cdot 1}

x = \frac{- ( - 20 ) + 18}{2 \cdot 1} : 19

x = \frac{- ( - 20 ) - 18}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 19, x = 1

x^{2} - 2 x + 193 = 0

2 x^{2} - 4 = 28

3 x^{2} - 5 x = - 7

2 x^{2} = 2 x

9 x^{2} = 12 x - 4

What are the solutions to the equation 2x^2-20x=x^2-19 ?
The solutions to the equation 2x^2-20x=x^2-19 are x=19,x=1
Find the zeros of 2x^2-20x=x^2-19
The zeros of 2x^2-20x=x^2-19 are x=19,x=1