What are the solutions to the equation -7x^2+17x+12=0 ?

The solutions to the equation -7x^2+17x+12=0 are x=-4/7 ,x=3

Find the zeros of -7x^2+17x+12=0

The zeros of -7x^2+17x+12=0 are x=-4/7 ,x=3

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- 7 x^{2} + 17 x + 12 = 0

x = - \frac{4}{7}, x = 3

Decimal Notation

x = - 0.57142 \dots, x = 3

Solution steps

- 7 x^{2} + 17 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 ( - 7 ) \cdot 12}{2 ( - 7 )}

1 7^{2} - 4 (- 7) \cdot 12 = 25

x_{1, 2} = \frac{- 17 \pm 25}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- 17 + 25}{2 ( - 7 )}, x_{2} = \frac{- 17 - 25}{2 ( - 7 )}

x = \frac{- 17 + 25}{2 ( - 7 )} : - \frac{4}{7}

x = \frac{- 17 - 25}{2 ( - 7 )} : 3

The solutions to the quadratic equation are:

x = - \frac{4}{7}, x = 3

4 - 2 a^{2} = - 7

x, 8 x^{2} - 6 y^{2} - 16 x + 24 y - 16 = 0

(4 x - 3) (5 x - 4) = 0

x^{2} - 18 x = - 31

x^{2} + 10 x + 22 = 13

What are the solutions to the equation -7x^2+17x+12=0 ?
The solutions to the equation -7x^2+17x+12=0 are x=-4/7 ,x=3
Find the zeros of -7x^2+17x+12=0
The zeros of -7x^2+17x+12=0 are x=-4/7 ,x=3