What are the solutions to the equation 4x^2-2x-2=0 ?

The solutions to the equation 4x^2-2x-2=0 are x=1,x=-1/2

Find the zeros of 4x^2-2x-2=0

The zeros of 4x^2-2x-2=0 are x=1,x=-1/2

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4 x^{2} - 2 x - 2 = 0

x = 1, x = - \frac{1}{2}

Decimal Notation

x = 1, x = - 0.5

Solution steps

4 x^{2} - 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

(- 2)^{2} - 4 \cdot 4 (- 2) = 6

x_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6}{2 \cdot 4}, x_{2} = \frac{- ( - 2 ) - 6}{2 \cdot 4}

x = \frac{- ( - 2 ) + 6}{2 \cdot 4} : 1

x = \frac{- ( - 2 ) - 6}{2 \cdot 4} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{2}

x^{2} + 5 x + 1

5 k^{2} - 9 k + 18 = 4 k^{2}

s^{2} + 4 s + 13

3 x^{2} + 66 = - 30 x

s^{2} + 4 s + 5

What are the solutions to the equation 4x^2-2x-2=0 ?
The solutions to the equation 4x^2-2x-2=0 are x=1,x=-1/2
Find the zeros of 4x^2-2x-2=0
The zeros of 4x^2-2x-2=0 are x=1,x=-1/2