What are the solutions to the equation 4x^2-12x=-17 ?

The solutions to the equation 4x^2-12x=-17 are x= 3/2+sqrt(2)i,x= 3/2-sqrt(2)i

Find the zeros of 4x^2-12x=-17

The zeros of 4x^2-12x=-17 are x= 3/2+sqrt(2)i,x= 3/2-sqrt(2)i

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4 x^{2} - 12 x = - 17

x = \frac{3}{2} + 2 i, x = \frac{3}{2} - 2 i

Solution steps

4 x^{2} - 12 x = - 17

Move

17

to the left side

4 x^{2} - 12 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 17}{2 \cdot 4}

Simplify

(- 12)^{2} - 4 \cdot 4 \cdot 17 : 82 i

x_{1, 2} = \frac{- ( - 12 ) \pm 8 2 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 8 2 i}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 8 2 i}{2 \cdot 4}

x = \frac{- ( - 12 ) + 8 2 i}{2 \cdot 4} : \frac{3}{2} + 2 i

x = \frac{- ( - 12 ) - 8 2 i}{2 \cdot 4} : \frac{3}{2} - 2 i

The solutions to the quadratic equation are:

x = \frac{3}{2} + 2 i, x = \frac{3}{2} - 2 i

x^{2} - 2 x = 7

a, y = (a - \frac{b}{x})^{2}

2 (x - 8)^{2} + 20 = 26

X^{2} + 6 X - 16 = 0

3 m^{2} - m - 11 = - 6

What are the solutions to the equation 4x^2-12x=-17 ?
The solutions to the equation 4x^2-12x=-17 are x= 3/2+sqrt(2)i,x= 3/2-sqrt(2)i
Find the zeros of 4x^2-12x=-17
The zeros of 4x^2-12x=-17 are x= 3/2+sqrt(2)i,x= 3/2-sqrt(2)i