What are the solutions to the equation 2x^2+12x+56=0 ?

The solutions to the equation 2x^2+12x+56=0 are x=-3+sqrt(19)i,x=-3-sqrt(19)i

Find the zeros of 2x^2+12x+56=0

The zeros of 2x^2+12x+56=0 are x=-3+sqrt(19)i,x=-3-sqrt(19)i

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2 x^{2} + 12 x + 56 = 0

x = - 3 + 19 i, x = - 3 - 19 i

Solution steps

2 x^{2} + 12 x + 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 \cdot 56}{2 \cdot 2}

Simplify

1 2^{2} - 4 \cdot 2 \cdot 56 : 419 i

x_{1, 2} = \frac{- 12 \pm 4 19 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 12 + 4 19 i}{2 \cdot 2}, x_{2} = \frac{- 12 - 4 19 i}{2 \cdot 2}

x = \frac{- 12 + 4 19 i}{2 \cdot 2} : - 3 + 19 i

x = \frac{- 12 - 4 19 i}{2 \cdot 2} : - 3 - 19 i

The solutions to the quadratic equation are:

x = - 3 + 19 i, x = - 3 - 19 i

b, s (t) = b^{2}

x^{2} - 3 x - 4 = 0

5 x^{2} + 10 x - 9 = 3 x - 3

X^{2} + X - 20 = 0

x^{2} = 19 x - 88

What are the solutions to the equation 2x^2+12x+56=0 ?
The solutions to the equation 2x^2+12x+56=0 are x=-3+sqrt(19)i,x=-3-sqrt(19)i
Find the zeros of 2x^2+12x+56=0
The zeros of 2x^2+12x+56=0 are x=-3+sqrt(19)i,x=-3-sqrt(19)i