What are the solutions to the equation -x^2+8x+20=0 ?

The solutions to the equation -x^2+8x+20=0 are x=-2,x=10

Find the zeros of -x^2+8x+20=0

The zeros of -x^2+8x+20=0 are x=-2,x=10

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- x^{2} + 8 x + 20 = 0

x = - 2, x = 10

Solution steps

- x^{2} + 8 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) \cdot 20}{2 ( - 1 )}

8^{2} - 4 (- 1) \cdot 20 = 12

x_{1, 2} = \frac{- 8 \pm 12}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 12}{2 ( - 1 )}, x_{2} = \frac{- 8 - 12}{2 ( - 1 )}

x = \frac{- 8 + 12}{2 ( - 1 )} : - 2

x = \frac{- 8 - 12}{2 ( - 1 )} : 10

The solutions to the quadratic equation are:

x = - 2, x = 10

x^{2} + 18 x - 27 = 0

2 x^{2} - 36 = 0

x, f = 2 x^{2} - 3 y - 4

8 x^{2} + 2 x - 1 = 0

x, 2 x^{2} + y^{2} - 4 x + 2 y + 3 = 0

What are the solutions to the equation -x^2+8x+20=0 ?
The solutions to the equation -x^2+8x+20=0 are x=-2,x=10
Find the zeros of -x^2+8x+20=0
The zeros of -x^2+8x+20=0 are x=-2,x=10