What are the solutions to the equation m^2-8m+16=0 ?

The solutions to the equation m^2-8m+16=0 are m=4

Find the zeros of m^2-8m+16=0

The zeros of m^2-8m+16=0 are m=4

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m^{2} - 8 m + 16 = 0

m = 4

Solution steps

m^{2} - 8 m + 16 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 16 = 0

m_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 1}

m = \frac{- ( - 8 )}{2 \cdot 1}

\frac{- ( - 8 )}{2 \cdot 1} = 4

m = 4

The solution to the quadratic equation is:

m = 4

36 x^{2} + 24 x = 0

(x - 4)^{2} = 169

2 x^{2} + 9 x + 6 = 0

x^{2} - 7 = 2 x + 3

x, y = 4 x - x^{2}

What are the solutions to the equation m^2-8m+16=0 ?
The solutions to the equation m^2-8m+16=0 are m=4
Find the zeros of m^2-8m+16=0
The zeros of m^2-8m+16=0 are m=4