What are the solutions to the equation 2x^2+9x+6=0 ?

The solutions to the equation 2x^2+9x+6=0 are x=(-9+sqrt(33))/4 ,x=(-9-sqrt(33))/4

Find the zeros of 2x^2+9x+6=0

The zeros of 2x^2+9x+6=0 are x=(-9+sqrt(33))/4 ,x=(-9-sqrt(33))/4

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2 x^{2} + 9 x + 6 = 0

x = \frac{- 9 + 33}{4}, x = \frac{- 9 - 33}{4}

Decimal

x = - 0.81385 \dots, x = - 3.68614 \dots

Solution steps

2 x^{2} + 9 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

9^{2} - 4 \cdot 2 \cdot 6 = 33

x_{1, 2} = \frac{- 9 \pm 33}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 9 + 33}{2 \cdot 2}, x_{2} = \frac{- 9 - 33}{2 \cdot 2}

x = \frac{- 9 + 33}{2 \cdot 2} : \frac{- 9 + 33}{4}

x = \frac{- 9 - 33}{2 \cdot 2} : \frac{- 9 - 33}{4}

The solutions to the quadratic equation are:

x = \frac{- 9 + 33}{4}, x = \frac{- 9 - 33}{4}

x^{2} - 7 = 2 x + 3

x, y = 4 x - x^{2}

4 x^{2} - 2 x - 3 = 0

2 x^{2} + 8 x - 3 = x + 1

10 + 5 b^{2} = 200

What are the solutions to the equation 2x^2+9x+6=0 ?
The solutions to the equation 2x^2+9x+6=0 are x=(-9+sqrt(33))/4 ,x=(-9-sqrt(33))/4
Find the zeros of 2x^2+9x+6=0
The zeros of 2x^2+9x+6=0 are x=(-9+sqrt(33))/4 ,x=(-9-sqrt(33))/4