What are the solutions to the equation x^2-16x+4=0 ?

The solutions to the equation x^2-16x+4=0 are x=2(4+sqrt(15)),x=2(4-sqrt(15))

Find the zeros of x^2-16x+4=0

The zeros of x^2-16x+4=0 are x=2(4+sqrt(15)),x=2(4-sqrt(15))

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x^{2} - 16 x + 4 = 0

x = 2 (4 + 15), x = 2 (4 - 15)

Decimal Notation

x = 15.74596 \dots, x = 0.25403 \dots

Solution steps

x^{2} - 16 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 4 = 415

x_{1, 2} = \frac{- ( - 16 ) \pm 4 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 15}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 4 15}{2 \cdot 1}

x = \frac{- ( - 16 ) + 4 15}{2 \cdot 1} : 2 (4 + 15)

x = \frac{- ( - 16 ) - 4 15}{2 \cdot 1} : 2 (4 - 15)

The solutions to the quadratic equation are:

x = 2 (4 + 15), x = 2 (4 - 15)

x, x^{2} + 4 x k + 1 = 0

x, y^{2} (x^{2} - 1) - 2 x = 0

2 x^{2} + 20 x = - 10

n^{2} = - 144

4 x^{2} - 4 x = - 5

What are the solutions to the equation x^2-16x+4=0 ?
The solutions to the equation x^2-16x+4=0 are x=2(4+sqrt(15)),x=2(4-sqrt(15))
Find the zeros of x^2-16x+4=0
The zeros of x^2-16x+4=0 are x=2(4+sqrt(15)),x=2(4-sqrt(15))