What are the solutions to the equation 2x^2+20x=-10 ?

The solutions to the equation 2x^2+20x=-10 are x=-5+2sqrt(5),x=-5-2sqrt(5)

Find the zeros of 2x^2+20x=-10

The zeros of 2x^2+20x=-10 are x=-5+2sqrt(5),x=-5-2sqrt(5)

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2 x^{2} + 20 x = - 10

x = - 5 + 25, x = - 5 - 25

Decimal Notation

x = - 0.52786 \dots, x = - 9.47213 \dots

Solution steps

2 x^{2} + 20 x = - 10

Move

10

to the left side

2 x^{2} + 20 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 2 \cdot 10}{2 \cdot 2}

2 0^{2} - 4 \cdot 2 \cdot 10 = 85

x_{1, 2} = \frac{- 20 \pm 8 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 20 + 8 5}{2 \cdot 2}, x_{2} = \frac{- 20 - 8 5}{2 \cdot 2}

x = \frac{- 20 + 8 5}{2 \cdot 2} : - 5 + 25

x = \frac{- 20 - 8 5}{2 \cdot 2} : - 5 - 25

The solutions to the quadratic equation are:

x = - 5 + 25, x = - 5 - 25

n^{2} = - 144

4 x^{2} - 4 x = - 5

x^{2} - 18 x + 81 = 49

2 (x + 10)^{2} - 37 = 13

x^{2} - 72 = 0

What are the solutions to the equation 2x^2+20x=-10 ?
The solutions to the equation 2x^2+20x=-10 are x=-5+2sqrt(5),x=-5-2sqrt(5)
Find the zeros of 2x^2+20x=-10
The zeros of 2x^2+20x=-10 are x=-5+2sqrt(5),x=-5-2sqrt(5)