What are the solutions to the equation 4(4x+9)^2-17=-5 ?

The solutions to the equation 4(4x+9)^2-17=-5 are x=(sqrt(3)-9)/4 ,x=(-sqrt(3)-9)/4

Find the zeros of 4(4x+9)^2-17=-5

The zeros of 4(4x+9)^2-17=-5 are x=(sqrt(3)-9)/4 ,x=(-sqrt(3)-9)/4

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4 (4 x + 9)^{2} - 17 = - 5

x = \frac{3 - 9}{4}, x = \frac{- 3 - 9}{4}

Decimal Notation

x = - 1.81698 \dots, x = - 2.68301 \dots

Solution steps

4 (4 x + 9)^{2} - 17 = - 5

Move

17

to the right side

4 (4 x + 9)^{2} = 12

Divide both sides by

4

(4 x + 9)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 9 = 3 : x = \frac{3 - 9}{4}

Solve

4 x + 9 = - 3 : x = \frac{- 3 - 9}{4}

The solutions to the quadratic equation are:

x = \frac{3 - 9}{4}, x = \frac{- 3 - 9}{4}

- 6 x^{2} - 7 x + 155 = - 8 x

a^{2} - 2 a - 3 = 0

y^{2} - 6 y

x^{2} + \frac{1}{2} x + 1 = 0

x, x^{2} + 3 x y + 1 = 0

What are the solutions to the equation 4(4x+9)^2-17=-5 ?
The solutions to the equation 4(4x+9)^2-17=-5 are x=(sqrt(3)-9)/4 ,x=(-sqrt(3)-9)/4
Find the zeros of 4(4x+9)^2-17=-5
The zeros of 4(4x+9)^2-17=-5 are x=(sqrt(3)-9)/4 ,x=(-sqrt(3)-9)/4