What are the solutions to the equation a^2-2a-3=0 ?

The solutions to the equation a^2-2a-3=0 are a=3,a=-1

Find the zeros of a^2-2a-3=0

The zeros of a^2-2a-3=0 are a=3,a=-1

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a^{2} - 2 a - 3 = 0

a = 3, a = - 1

Solution steps

a^{2} - 2 a - 3 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 3) = 4

a_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 2 ) + 4}{2 \cdot 1}, a_{2} = \frac{- ( - 2 ) - 4}{2 \cdot 1}

a = \frac{- ( - 2 ) + 4}{2 \cdot 1} : 3

a = \frac{- ( - 2 ) - 4}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

a = 3, a = - 1

y^{2} - 6 y

x^{2} + \frac{1}{2} x + 1 = 0

x, x^{2} + 3 x y + 1 = 0

4 x^{2} + 16 x + 3 = 8 x

x^{2} - 8 x - 63 = - 10 x

What are the solutions to the equation a^2-2a-3=0 ?
The solutions to the equation a^2-2a-3=0 are a=3,a=-1
Find the zeros of a^2-2a-3=0
The zeros of a^2-2a-3=0 are a=3,a=-1