What are the solutions to the equation r^2+2r-33=0 ?

The solutions to the equation r^2+2r-33=0 are r=-1+sqrt(34),r=-1-sqrt(34)

Find the zeros of r^2+2r-33=0

The zeros of r^2+2r-33=0 are r=-1+sqrt(34),r=-1-sqrt(34)

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r^{2} + 2 r - 33 = 0

r = - 1 + 34, r = - 1 - 34

Decimal Notation

r = 4.83095 \dots, r = - 6.83095 \dots

Solution steps

r^{2} + 2 r - 33 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 33 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 33) = 234

r_{1, 2} = \frac{- 2 \pm 2 34}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 2 + 2 34}{2 \cdot 1}, r_{2} = \frac{- 2 - 2 34}{2 \cdot 1}

r = \frac{- 2 + 2 34}{2 \cdot 1} : - 1 + 34

r = \frac{- 2 - 2 34}{2 \cdot 1} : - 1 - 34

The solutions to the quadratic equation are:

r = - 1 + 34, r = - 1 - 34

12 x^{2} + 27 x + 15

4 x - 5 + 2 (x - 3) = 12 x + 7

2 x^{2} - 6 x = - 5

\frac{x ^{\frac{1}{2}} y ^{2}}{4 x ^{5} y}

ln (\frac{a ^{3}}{b})

What are the solutions to the equation r^2+2r-33=0 ?
The solutions to the equation r^2+2r-33=0 are r=-1+sqrt(34),r=-1-sqrt(34)
Find the zeros of r^2+2r-33=0
The zeros of r^2+2r-33=0 are r=-1+sqrt(34),r=-1-sqrt(34)