What are the solutions to the equation 2x^2-6x=-5 ?

The solutions to the equation 2x^2-6x=-5 are x= 3/2+i 1/2 ,x= 3/2-i 1/2

Find the zeros of 2x^2-6x=-5

The zeros of 2x^2-6x=-5 are x= 3/2+i 1/2 ,x= 3/2-i 1/2

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2 x^{2} - 6 x = - 5

x = \frac{3}{2} + i \frac{1}{2}, x = \frac{3}{2} - i \frac{1}{2}

Solution steps

2 x^{2} - 6 x = - 5

Move

5

to the left side

2 x^{2} - 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 \cdot 5}{2 \cdot 2}

Simplify

(- 6)^{2} - 4 \cdot 2 \cdot 5 : 2 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 i}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 2 i}{2 \cdot 2}

x = \frac{- ( - 6 ) + 2 i}{2 \cdot 2} : \frac{3}{2} + i \frac{1}{2}

x = \frac{- ( - 6 ) - 2 i}{2 \cdot 2} : \frac{3}{2} - i \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{1}{2}, x = \frac{3}{2} - i \frac{1}{2}

\frac{x ^{\frac{1}{2}} y ^{2}}{4 x ^{5} y}

ln (\frac{a ^{3}}{b})

5 x - 5 \geq - 2

0 = - 16 t^{2} + 112 t

2 x^{2} - 19 x + 9 = 0

What are the solutions to the equation 2x^2-6x=-5 ?
The solutions to the equation 2x^2-6x=-5 are x= 3/2+i 1/2 ,x= 3/2-i 1/2
Find the zeros of 2x^2-6x=-5
The zeros of 2x^2-6x=-5 are x= 3/2+i 1/2 ,x= 3/2-i 1/2