What are the solutions to the equation 5a^2-2a=-16 ?

The solutions to the equation 5a^2-2a=-16 are a= 1/5+i(sqrt(79))/5 ,a= 1/5-i(sqrt(79))/5

Find the zeros of 5a^2-2a=-16

The zeros of 5a^2-2a=-16 are a= 1/5+i(sqrt(79))/5 ,a= 1/5-i(sqrt(79))/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 a^{2} - 2 a = - 16

a = \frac{1}{5} + i \frac{79}{5}, a = \frac{1}{5} - i \frac{79}{5}

Solution steps

5 a^{2} - 2 a = - 16

Move

16

to the left side

5 a^{2} - 2 a + 16 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 5 \cdot 16}{2 \cdot 5}

Simplify

(- 2)^{2} - 4 \cdot 5 \cdot 16 : 279 i

a_{1, 2} = \frac{- ( - 2 ) \pm 2 79 i}{2 \cdot 5}

Separate the solutions

a_{1} = \frac{- ( - 2 ) + 2 79 i}{2 \cdot 5}, a_{2} = \frac{- ( - 2 ) - 2 79 i}{2 \cdot 5}

a = \frac{- ( - 2 ) + 2 79 i}{2 \cdot 5} : \frac{1}{5} + i \frac{79}{5}

a = \frac{- ( - 2 ) - 2 79 i}{2 \cdot 5} : \frac{1}{5} - i \frac{79}{5}

The solutions to the quadratic equation are:

a = \frac{1}{5} + i \frac{79}{5}, a = \frac{1}{5} - i \frac{79}{5}

y, y = x^{2} + y

m^{2} - 6 m - 17 = - 5

1.15 (0.85 - 2 x)^{2} = x

5 n^{2} - 2 = - 92

3 (x - 3)^{2} + 2 = 26

What are the solutions to the equation 5a^2-2a=-16 ?
The solutions to the equation 5a^2-2a=-16 are a= 1/5+i(sqrt(79))/5 ,a= 1/5-i(sqrt(79))/5
Find the zeros of 5a^2-2a=-16
The zeros of 5a^2-2a=-16 are a= 1/5+i(sqrt(79))/5 ,a= 1/5-i(sqrt(79))/5