What are the solutions to the equation 6x^2-17x+6=0 ?

The solutions to the equation 6x^2-17x+6=0 are x=(17+sqrt(145))/(12),x=(17-sqrt(145))/(12)

Find the zeros of 6x^2-17x+6=0

The zeros of 6x^2-17x+6=0 are x=(17+sqrt(145))/(12),x=(17-sqrt(145))/(12)

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6 x^{2} - 17 x + 6 = 0

x = \frac{17 + 145}{12}, x = \frac{17 - 145}{12}

Decimal Notation

x = 2.42013 \dots, x = 0.41320 \dots

Solution steps

6 x^{2} - 17 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 6 \cdot 6}{2 \cdot 6}

(- 17)^{2} - 4 \cdot 6 \cdot 6 = 145

x_{1, 2} = \frac{- ( - 17 ) \pm 145}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 145}{2 \cdot 6}, x_{2} = \frac{- ( - 17 ) - 145}{2 \cdot 6}

x = \frac{- ( - 17 ) + 145}{2 \cdot 6} : \frac{17 + 145}{12}

x = \frac{- ( - 17 ) - 145}{2 \cdot 6} : \frac{17 - 145}{12}

The solutions to the quadratic equation are:

x = \frac{17 + 145}{12}, x = \frac{17 - 145}{12}

(5 x - 2)^{2} - (3 x + 1)^{2} - x^{2} - 60 = 0

x^{2} - 8 x - 11 = 0

3 x^{2} - 32 x + 64 = 0

x^{2} + 6 x + 4

0 = x^{2} - 2 x - 8

What are the solutions to the equation 6x^2-17x+6=0 ?
The solutions to the equation 6x^2-17x+6=0 are x=(17+sqrt(145))/(12),x=(17-sqrt(145))/(12)
Find the zeros of 6x^2-17x+6=0
The zeros of 6x^2-17x+6=0 are x=(17+sqrt(145))/(12),x=(17-sqrt(145))/(12)