What are the solutions to the equation 3x^2-32x+64=0 ?

The solutions to the equation 3x^2-32x+64=0 are x=8,x= 8/3

Find the zeros of 3x^2-32x+64=0

The zeros of 3x^2-32x+64=0 are x=8,x= 8/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 32 x + 64 = 0

x = 8, x = \frac{8}{3}

Decimal Notation

x = 8, x = 2.66666 \dots

Solution steps

3 x^{2} - 32 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 32 ) \pm ( - 32 ) ^{2} - 4 \cdot 3 \cdot 64}{2 \cdot 3}

(- 32)^{2} - 4 \cdot 3 \cdot 64 = 16

x_{1, 2} = \frac{- ( - 32 ) \pm 16}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 32 ) + 16}{2 \cdot 3}, x_{2} = \frac{- ( - 32 ) - 16}{2 \cdot 3}

x = \frac{- ( - 32 ) + 16}{2 \cdot 3} : 8

x = \frac{- ( - 32 ) - 16}{2 \cdot 3} : \frac{8}{3}

The solutions to the quadratic equation are:

x = 8, x = \frac{8}{3}

x^{2} + 6 x + 4

0 = x^{2} - 2 x - 8

x^{2} - 2 x - 24 = 0

x^{2} - 3 x - 15 = 0

4 x^{2} + 10 x - 3 = 0

What are the solutions to the equation 3x^2-32x+64=0 ?
The solutions to the equation 3x^2-32x+64=0 are x=8,x= 8/3
Find the zeros of 3x^2-32x+64=0
The zeros of 3x^2-32x+64=0 are x=8,x= 8/3