What are the solutions to the equation x^2-3x-15=0 ?

The solutions to the equation x^2-3x-15=0 are x=(3+sqrt(69))/2 ,x=(3-sqrt(69))/2

Find the zeros of x^2-3x-15=0

The zeros of x^2-3x-15=0 are x=(3+sqrt(69))/2 ,x=(3-sqrt(69))/2

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x^{2} - 3 x - 15 = 0

x = \frac{3 + 69}{2}, x = \frac{3 - 69}{2}

Decimal Notation

x = 5.65331 \dots, x = - 2.65331 \dots

Solution steps

x^{2} - 3 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 15) = 69

x_{1, 2} = \frac{- ( - 3 ) \pm 69}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 69}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 69}{2 \cdot 1}

x = \frac{- ( - 3 ) + 69}{2 \cdot 1} : \frac{3 + 69}{2}

x = \frac{- ( - 3 ) - 69}{2 \cdot 1} : \frac{3 - 69}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 69}{2}, x = \frac{3 - 69}{2}

4 x^{2} + 10 x - 3 = 0

3 x^{2} + 8 x = 6 x + 1

A = x^{2} - 18 x + 80

a^{2} x^{2} + ab x = 6 b^{2}

6 t^{2} - 2 t + 2 = 4 t + t

What are the solutions to the equation x^2-3x-15=0 ?
The solutions to the equation x^2-3x-15=0 are x=(3+sqrt(69))/2 ,x=(3-sqrt(69))/2
Find the zeros of x^2-3x-15=0
The zeros of x^2-3x-15=0 are x=(3+sqrt(69))/2 ,x=(3-sqrt(69))/2