What are the solutions to the equation A=x^2-18x+80 ?

The solutions to the equation A=x^2-18x+80 are x=9+sqrt(A+1),x=9-sqrt(A+1)

Find the zeros of A=x^2-18x+80

The zeros of A=x^2-18x+80 are x=9+sqrt(A+1),x=9-sqrt(A+1)

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A = x^{2} - 18 x + 80

x = 9 + A + 1, x = 9 - A + 1

Solution steps

A = x^{2} - 18 x + 80

Switch sides

x^{2} - 18 x + 80 = A

Move

A

to the left side

x^{2} - 18 x + 80 - A = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot ( 80 - A )}{2 \cdot 1}

Simplify

(- 18)^{2} - 4 \cdot 1 \cdot (80 - A) : 2 A + 1

x_{1, 2} = \frac{- ( - 18 ) \pm 2 A + 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2 A + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 2 A + 1}{2 \cdot 1}

x = \frac{- ( - 18 ) + 2 A + 1}{2 \cdot 1} : 9 + A + 1

x = \frac{- ( - 18 ) - 2 A + 1}{2 \cdot 1} : 9 - A + 1

The solutions to the quadratic equation are:

x = 9 + A + 1, x = 9 - A + 1

a^{2} x^{2} + ab x = 6 b^{2}

6 t^{2} - 2 t + 2 = 4 t + t

4 x^{2} + 2 x - 5 = 0

x^{2} + 40 x + 2000 = 0

176 x = 121 + 64 x^{2}

What are the solutions to the equation A=x^2-18x+80 ?
The solutions to the equation A=x^2-18x+80 are x=9+sqrt(A+1),x=9-sqrt(A+1)
Find the zeros of A=x^2-18x+80
The zeros of A=x^2-18x+80 are x=9+sqrt(A+1),x=9-sqrt(A+1)