What are the solutions to the equation (x-3)^2+27=0 ?

The solutions to the equation (x-3)^2+27=0 are x=3sqrt(3)i+3,x=-3sqrt(3)i+3

Find the zeros of (x-3)^2+27=0

The zeros of (x-3)^2+27=0 are x=3sqrt(3)i+3,x=-3sqrt(3)i+3

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(x - 3)^{2} + 27 = 0

x = 33 i + 3, x = - 33 i + 3

Solution steps

(x - 3)^{2} + 27 = 0

Move

27

to the right side

(x - 3)^{2} = - 27

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = - 27 : x = 33 i + 3

Solve

x - 3 = - - 27 : x = - 33 i + 3

The solutions to the quadratic equation are:

x = 33 i + 3, x = - 33 i + 3

3 x^{2} - 42 x = - 87

x, x^{2} + x y + y^{2} = 0

x^{2} - 10 x + 5

x^{2} - 10 x + 31 = 0

a^{2} - a - 2 = 0

What are the solutions to the equation (x-3)^2+27=0 ?
The solutions to the equation (x-3)^2+27=0 are x=3sqrt(3)i+3,x=-3sqrt(3)i+3
Find the zeros of (x-3)^2+27=0
The zeros of (x-3)^2+27=0 are x=3sqrt(3)i+3,x=-3sqrt(3)i+3