What are the solutions to the equation 3x^2-42x=-87 ?

The solutions to the equation 3x^2-42x=-87 are x=7+2sqrt(5),x=7-2sqrt(5)

Find the zeros of 3x^2-42x=-87

The zeros of 3x^2-42x=-87 are x=7+2sqrt(5),x=7-2sqrt(5)

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3 x^{2} - 42 x = - 87

x = 7 + 25, x = 7 - 25

Decimal Notation

x = 11.47213 \dots, x = 2.52786 \dots

Solution steps

3 x^{2} - 42 x = - 87

Move

87

to the left side

3 x^{2} - 42 x + 87 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 42 ) \pm ( - 42 ) ^{2} - 4 \cdot 3 \cdot 87}{2 \cdot 3}

(- 42)^{2} - 4 \cdot 3 \cdot 87 = 125

x_{1, 2} = \frac{- ( - 42 ) \pm 12 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 42 ) + 12 5}{2 \cdot 3}, x_{2} = \frac{- ( - 42 ) - 12 5}{2 \cdot 3}

x = \frac{- ( - 42 ) + 12 5}{2 \cdot 3} : 7 + 25

x = \frac{- ( - 42 ) - 12 5}{2 \cdot 3} : 7 - 25

The solutions to the quadratic equation are:

x = 7 + 25, x = 7 - 25

x, x^{2} + x y + y^{2} = 0

x^{2} - 10 x + 5

x^{2} - 10 x + 31 = 0

a^{2} - a - 2 = 0

- 2 x^{2} - 28 x - 102 = 0

What are the solutions to the equation 3x^2-42x=-87 ?
The solutions to the equation 3x^2-42x=-87 are x=7+2sqrt(5),x=7-2sqrt(5)
Find the zeros of 3x^2-42x=-87
The zeros of 3x^2-42x=-87 are x=7+2sqrt(5),x=7-2sqrt(5)