What are the solutions to the equation x^2+12x+36=100 ?

The solutions to the equation x^2+12x+36=100 are x=4,x=-16

Find the zeros of x^2+12x+36=100

The zeros of x^2+12x+36=100 are x=4,x=-16

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x^{2} + 12 x + 36 = 100

x = 4, x = - 16

Solution steps

x^{2} + 12 x + 36 = 100

Move

100

to the left side

x^{2} + 12 x - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 64 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 64) = 20

x_{1, 2} = \frac{- 12 \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 20}{2 \cdot 1}, x_{2} = \frac{- 12 - 20}{2 \cdot 1}

x = \frac{- 12 + 20}{2 \cdot 1} : 4

x = \frac{- 12 - 20}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

x = 4, x = - 16

x^{2} + 4 x - 7

24 = x^{2} - 4 x + 3

x, x^{2} y^{2} - x y + x = 1

r, v = \frac{1}{3} (π r^{2}) h

2 x^{2} + 16 x + 14 = 0

What are the solutions to the equation x^2+12x+36=100 ?
The solutions to the equation x^2+12x+36=100 are x=4,x=-16
Find the zeros of x^2+12x+36=100
The zeros of x^2+12x+36=100 are x=4,x=-16