What are the solutions to the equation x(x-9)+18=0 ?

The solutions to the equation x(x-9)+18=0 are x=6,x=3

Find the zeros of x(x-9)+18=0

The zeros of x(x-9)+18=0 are x=6,x=3

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x (x - 9) + 18 = 0

x = 6, x = 3

Solution steps

x (x - 9) + 18 = 0

Expand

x (x - 9) + 18 : x^{2} - 9 x + 18

x^{2} - 9 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 18 = 3

x_{1, 2} = \frac{- ( - 9 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 3}{2 \cdot 1}

x = \frac{- ( - 9 ) + 3}{2 \cdot 1} : 6

x = \frac{- ( - 9 ) - 3}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 6, x = 3

4 z^{2} - 20 = 0

∣ 2 x + 1 ∣ = 7

x^{6} + 7 x^{3} - 8

- 5 x - 9 < 11

5^{2} \cdot 5^{- 6}

What are the solutions to the equation x(x-9)+18=0 ?
The solutions to the equation x(x-9)+18=0 are x=6,x=3
Find the zeros of x(x-9)+18=0
The zeros of x(x-9)+18=0 are x=6,x=3