What are the solutions to the equation 48a^2-279a=-210+3a ?

The solutions to the equation 48a^2-279a=-210+3a are a=5,a= 7/8

Find the zeros of 48a^2-279a=-210+3a

The zeros of 48a^2-279a=-210+3a are a=5,a= 7/8

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48 a^{2} - 279 a = - 210 + 3 a

a = 5, a = \frac{7}{8}

Decimal Notation

a = 5, a = 0.875

Solution steps

48 a^{2} - 279 a = - 210 + 3 a

Move

3 a

to the left side

48 a^{2} - 282 a = - 210

Move

210

to the left side

48 a^{2} - 282 a + 210 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 282 ) \pm ( - 282 ) ^{2} - 4 \cdot 48 \cdot 210}{2 \cdot 48}

(- 282)^{2} - 4 \cdot 48 \cdot 210 = 198

a_{1, 2} = \frac{- ( - 282 ) \pm 198}{2 \cdot 48}

Separate the solutions

a_{1} = \frac{- ( - 282 ) + 198}{2 \cdot 48}, a_{2} = \frac{- ( - 282 ) - 198}{2 \cdot 48}

a = \frac{- ( - 282 ) + 198}{2 \cdot 48} : 5

a = \frac{- ( - 282 ) - 198}{2 \cdot 48} : \frac{7}{8}

The solutions to the quadratic equation are:

a = 5, a = \frac{7}{8}

24 x^{2} + 2 x = 15

(x + 5) (x - 3) = 0

5 x^{2} + 2 x + 3 = 0

x^{2} - 12 x + 36 = 9

x, f = x^{2} + x y^{2} - z^{2}

What are the solutions to the equation 48a^2-279a=-210+3a ?
The solutions to the equation 48a^2-279a=-210+3a are a=5,a= 7/8
Find the zeros of 48a^2-279a=-210+3a
The zeros of 48a^2-279a=-210+3a are a=5,a= 7/8