What are the solutions to the equation x^2+x=306 ?

The solutions to the equation x^2+x=306 are x=17,x=-18

Find the zeros of x^2+x=306

The zeros of x^2+x=306 are x=17,x=-18

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x^{2} + x = 306

x = 17, x = - 18

Solution steps

x^{2} + x = 306

Move

306

to the left side

x^{2} + x - 306 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 306 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 306) = 35

x_{1, 2} = \frac{- 1 \pm 35}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 35}{2 \cdot 1}, x_{2} = \frac{- 1 - 35}{2 \cdot 1}

x = \frac{- 1 + 35}{2 \cdot 1} : 17

x = \frac{- 1 - 35}{2 \cdot 1} : - 18

The solutions to the quadratic equation are:

x = 17, x = - 18

x, x^{2} y - 1 = 9 x - 2 y^{2}

x^{2} - 4 x = 0

x^{2} + 17 = - 10 x - 7

2 5^{2} = 2 4^{2} + x^{2}

5 (x + 2)^{2} = - 125

What are the solutions to the equation x^2+x=306 ?
The solutions to the equation x^2+x=306 are x=17,x=-18
Find the zeros of x^2+x=306
The zeros of x^2+x=306 are x=17,x=-18