What are the solutions to the equation 4(x-10)^2+20=24 ?

The solutions to the equation 4(x-10)^2+20=24 are x=11,x=9

Find the zeros of 4(x-10)^2+20=24

The zeros of 4(x-10)^2+20=24 are x=11,x=9

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4 (x - 10)^{2} + 20 = 24

x = 11, x = 9

Solution steps

4 (x - 10)^{2} + 20 = 24

Move

20

to the right side

4 (x - 10)^{2} = 4

Divide both sides by

4

(x - 10)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 10 = 1 : x = 11

Solve

x - 10 = - 1 : x = 9

The solutions to the quadratic equation are:

x = 11, x = 9

16 x^{2} + 48 x + 36 = 0

- x^{2} = 64

x^{2} - 2 x - 26 = 0

0 = 3 x^{2} - 6 x - 9

(x + 3)^{2} = - 54

What are the solutions to the equation 4(x-10)^2+20=24 ?
The solutions to the equation 4(x-10)^2+20=24 are x=11,x=9
Find the zeros of 4(x-10)^2+20=24
The zeros of 4(x-10)^2+20=24 are x=11,x=9