What are the solutions to the equation x^2-2x-26=0 ?

The solutions to the equation x^2-2x-26=0 are x=1+3sqrt(3),x=1-3sqrt(3)

Find the zeros of x^2-2x-26=0

The zeros of x^2-2x-26=0 are x=1+3sqrt(3),x=1-3sqrt(3)

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x^{2} - 2 x - 26 = 0

x = 1 + 33, x = 1 - 33

Decimal Notation

x = 6.19615 \dots, x = - 4.19615 \dots

Solution steps

x^{2} - 2 x - 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 26 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 26) = 63

x_{1, 2} = \frac{- ( - 2 ) \pm 6 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6 3}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 6 3}{2 \cdot 1}

x = \frac{- ( - 2 ) + 6 3}{2 \cdot 1} : 1 + 33

x = \frac{- ( - 2 ) - 6 3}{2 \cdot 1} : 1 - 33

The solutions to the quadratic equation are:

x = 1 + 33, x = 1 - 33

0 = 3 x^{2} - 6 x - 9

(x + 3)^{2} = - 54

3 x^{2} + 18 x + 8

x, x^{2} + y^{2} = y^{3} + 2 x - y

4 x^{2} - 3 = 12 x

What are the solutions to the equation x^2-2x-26=0 ?
The solutions to the equation x^2-2x-26=0 are x=1+3sqrt(3),x=1-3sqrt(3)
Find the zeros of x^2-2x-26=0
The zeros of x^2-2x-26=0 are x=1+3sqrt(3),x=1-3sqrt(3)