What are the solutions to the equation -2x^2+x-4=0 ?

The solutions to the equation -2x^2+x-4=0 are x= 1/4-i(sqrt(31))/4 ,x= 1/4+i(sqrt(31))/4

Find the zeros of -2x^2+x-4=0

The zeros of -2x^2+x-4=0 are x= 1/4-i(sqrt(31))/4 ,x= 1/4+i(sqrt(31))/4

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- 2 x^{2} + x - 4 = 0

x = \frac{1}{4} - i \frac{31}{4}, x = \frac{1}{4} + i \frac{31}{4}

Solution steps

- 2 x^{2} + x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) ( - 4 )}{2 ( - 2 )}

Simplify

1^{2} - 4 (- 2) (- 4) : 31 i

x_{1, 2} = \frac{- 1 \pm 31 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 1 + 31 i}{2 ( - 2 )}, x_{2} = \frac{- 1 - 31 i}{2 ( - 2 )}

x = \frac{- 1 + 31 i}{2 ( - 2 )} : \frac{1}{4} - i \frac{31}{4}

x = \frac{- 1 - 31 i}{2 ( - 2 )} : \frac{1}{4} + i \frac{31}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} - i \frac{31}{4}, x = \frac{1}{4} + i \frac{31}{4}

x^{2} - 6 x + 4

6 x^{2} - 36 x + 72 = 0

(q + \frac{5}{4})^{2} + 7 = - 18

x^{2} + 20 x + 100 = 64

0 = x^{2} - 8 x + 12

What are the solutions to the equation -2x^2+x-4=0 ?
The solutions to the equation -2x^2+x-4=0 are x= 1/4-i(sqrt(31))/4 ,x= 1/4+i(sqrt(31))/4
Find the zeros of -2x^2+x-4=0
The zeros of -2x^2+x-4=0 are x= 1/4-i(sqrt(31))/4 ,x= 1/4+i(sqrt(31))/4