What are the solutions to the equation 2x^2+17x-3=10x-9 ?

The solutions to the equation 2x^2+17x-3=10x-9 are x=-3/2 ,x=-2

Find the zeros of 2x^2+17x-3=10x-9

The zeros of 2x^2+17x-3=10x-9 are x=-3/2 ,x=-2

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2 x^{2} + 17 x - 3 = 10 x - 9

x = - \frac{3}{2}, x = - 2

Decimal Notation

x = - 1.5, x = - 2

Solution steps

2 x^{2} + 17 x - 3 = 10 x - 9

Move

9

to the left side

2 x^{2} + 17 x + 6 = 10 x

Move

10 x

to the left side

2 x^{2} + 7 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

7^{2} - 4 \cdot 2 \cdot 6 = 1

x_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 1}{2 \cdot 2}, x_{2} = \frac{- 7 - 1}{2 \cdot 2}

x = \frac{- 7 + 1}{2 \cdot 2} : - \frac{3}{2}

x = \frac{- 7 - 1}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = - 2

5 x^{2} - 80 x + 75 = 0

8 - 2 x^{2} = 0

x^{2} + 8 x + 16 = 9

b, s (t) = b^{2} t

x, 2 x^{2} - 3 y^{2} + 4 x + 6 y - 1 = 0

What are the solutions to the equation 2x^2+17x-3=10x-9 ?
The solutions to the equation 2x^2+17x-3=10x-9 are x=-3/2 ,x=-2
Find the zeros of 2x^2+17x-3=10x-9
The zeros of 2x^2+17x-3=10x-9 are x=-3/2 ,x=-2