What are the solutions to the equation x^2+8x+16=9 ?

The solutions to the equation x^2+8x+16=9 are x=-1,x=-7

Find the zeros of x^2+8x+16=9

The zeros of x^2+8x+16=9 are x=-1,x=-7

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x^{2} + 8 x + 16 = 9

x = - 1, x = - 7

Solution steps

x^{2} + 8 x + 16 = 9

Move

9

to the left side

x^{2} + 8 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 7 = 6

x_{1, 2} = \frac{- 8 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 6}{2 \cdot 1}, x_{2} = \frac{- 8 - 6}{2 \cdot 1}

x = \frac{- 8 + 6}{2 \cdot 1} : - 1

x = \frac{- 8 - 6}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = - 1, x = - 7

b, s (t) = b^{2} t

x, 2 x^{2} - 3 y^{2} + 4 x + 6 y - 1 = 0

x^{2} + 4 x + 3 = 0

x^{2} = - 12 x

11 x^{2} - 9 x + 1 = 6 x^{2}

What are the solutions to the equation x^2+8x+16=9 ?
The solutions to the equation x^2+8x+16=9 are x=-1,x=-7
Find the zeros of x^2+8x+16=9
The zeros of x^2+8x+16=9 are x=-1,x=-7