What are the solutions to the equation x^2=-12x ?

The solutions to the equation x^2=-12x are x=0,x=-12

Find the zeros of x^2=-12x

The zeros of x^2=-12x are x=0,x=-12

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x^{2} = - 12 x

x = 0, x = - 12

Solution steps

x^{2} = - 12 x

Move

12 x

to the left side

x^{2} + 12 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 0 = 12

x_{1, 2} = \frac{- 12 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 12}{2 \cdot 1}, x_{2} = \frac{- 12 - 12}{2 \cdot 1}

x = \frac{- 12 + 12}{2 \cdot 1} : 0

x = \frac{- 12 - 12}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = 0, x = - 12

11 x^{2} - 9 x + 1 = 6 x^{2}

x^{2} + 16 x - 2 = 11

2 (4 x - 10)^{2} = 26

x^{2} + 98 = 8 x + 7

x^{2} + 18 x + 45 = 0

What are the solutions to the equation x^2=-12x ?
The solutions to the equation x^2=-12x are x=0,x=-12
Find the zeros of x^2=-12x
The zeros of x^2=-12x are x=0,x=-12