What are the solutions to the equation x^2-2ax+a^2-b^2=0 ?

The solutions to the equation x^2-2ax+a^2-b^2=0 are x=a+b,x=a-b

Find the zeros of x^2-2ax+a^2-b^2=0

The zeros of x^2-2ax+a^2-b^2=0 are x=a+b,x=a-b

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x^{2} - 2 a x + a^{2} - b^{2} = 0

x = a + b, x = a - b

Solution steps

x^{2} - 2 a x + a^{2} - b^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 a ) \pm ( - 2 a ) ^{2} - 4 \cdot 1 \cdot ( a ^{2} - b ^{2} )}{2 \cdot 1}

Simplify

(- 2 a)^{2} - 4 \cdot 1 \cdot (a^{2} - b^{2}) : 2 b

x_{1, 2} = \frac{- ( - 2 a ) \pm 2 b}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 a ) + 2 b}{2 \cdot 1}, x_{2} = \frac{- ( - 2 a ) - 2 b}{2 \cdot 1}

x = \frac{- ( - 2 a ) + 2 b}{2 \cdot 1} : a + b

x = \frac{- ( - 2 a ) - 2 b}{2 \cdot 1} : a - b

The solutions to the quadratic equation are:

x = a + b, x = a - b

x^{2} + 9 x

27 a y - 14 y^{2} = 10 a^{2}

x^{2} + 11 x + 11 = 4 x

x^{2} - 5 x = 0

x - 36 = x^{2} - 11 x

What are the solutions to the equation x^2-2ax+a^2-b^2=0 ?
The solutions to the equation x^2-2ax+a^2-b^2=0 are x=a+b,x=a-b
Find the zeros of x^2-2ax+a^2-b^2=0
The zeros of x^2-2ax+a^2-b^2=0 are x=a+b,x=a-b