What are the solutions to the equation x^2+12x+15=75 ?

The solutions to the equation x^2+12x+15=75 are x=2(2sqrt(6)-3),x=-2(3+2sqrt(6))

Find the zeros of x^2+12x+15=75

The zeros of x^2+12x+15=75 are x=2(2sqrt(6)-3),x=-2(3+2sqrt(6))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 12 x + 15 = 75

x = 2 (26 - 3), x = - 2 (3 + 26)

Decimal Notation

x = 3.79795 \dots, x = - 15.79795 \dots

Solution steps

x^{2} + 12 x + 15 = 75

Move

75

to the left side

x^{2} + 12 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 60 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 60) = 86

x_{1, 2} = \frac{- 12 \pm 8 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 8 6}{2 \cdot 1}, x_{2} = \frac{- 12 - 8 6}{2 \cdot 1}

x = \frac{- 12 + 8 6}{2 \cdot 1} : 2 (26 - 3)

x = \frac{- 12 - 8 6}{2 \cdot 1} : - 2 (3 + 26)

The solutions to the quadratic equation are:

x = 2 (26 - 3), x = - 2 (3 + 26)

m^{2} - 10 m + 13 = 0

2 x^{2} - 11 x + 7 = 0

4 (4 x + 2)^{2} - 19 = 37

4 x^{2} - 8.5 x + 1 = 0

r^{2} = 16

What are the solutions to the equation x^2+12x+15=75 ?
The solutions to the equation x^2+12x+15=75 are x=2(2sqrt(6)-3),x=-2(3+2sqrt(6))
Find the zeros of x^2+12x+15=75
The zeros of x^2+12x+15=75 are x=2(2sqrt(6)-3),x=-2(3+2sqrt(6))