What are the solutions to the equation 4(4x+2)^2-19=37 ?

The solutions to the equation 4(4x+2)^2-19=37 are x=(sqrt(14)-2)/4 ,x=(-sqrt(14)-2)/4

Find the zeros of 4(4x+2)^2-19=37

The zeros of 4(4x+2)^2-19=37 are x=(sqrt(14)-2)/4 ,x=(-sqrt(14)-2)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 (4 x + 2)^{2} - 19 = 37

x = \frac{14 - 2}{4}, x = \frac{- 14 - 2}{4}

Decimal Notation

x = 0.43541 \dots, x = - 1.43541 \dots

Solution steps

4 (4 x + 2)^{2} - 19 = 37

Move

19

to the right side

4 (4 x + 2)^{2} = 56

Divide both sides by

4

(4 x + 2)^{2} = 14

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 2 = 14 : x = \frac{14 - 2}{4}

Solve

4 x + 2 = - 14 : x = \frac{- 14 - 2}{4}

The solutions to the quadratic equation are:

x = \frac{14 - 2}{4}, x = \frac{- 14 - 2}{4}

4 x^{2} - 8.5 x + 1 = 0

r^{2} = 16

(x) (x - 3) = 0

x^{2} + x - \frac{3}{4} = 0

f, h = f (g + f)

What are the solutions to the equation 4(4x+2)^2-19=37 ?
The solutions to the equation 4(4x+2)^2-19=37 are x=(sqrt(14)-2)/4 ,x=(-sqrt(14)-2)/4
Find the zeros of 4(4x+2)^2-19=37
The zeros of 4(4x+2)^2-19=37 are x=(sqrt(14)-2)/4 ,x=(-sqrt(14)-2)/4