What are the solutions to the equation n^2-2n=15 ?

The solutions to the equation n^2-2n=15 are n=5,n=-3

Find the zeros of n^2-2n=15

The zeros of n^2-2n=15 are n=5,n=-3

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n^{2} - 2 n = 15

n = 5, n = - 3

Solution steps

n^{2} - 2 n = 15

Move

15

to the left side

n^{2} - 2 n - 15 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 15) = 8

n_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 1}, n_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 1}

n = \frac{- ( - 2 ) + 8}{2 \cdot 1} : 5

n = \frac{- ( - 2 ) - 8}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

n = 5, n = - 3

(x - \frac{1}{4}) (x + \frac{1}{4}) = \frac{3}{16}

5 x - x^{2} = 2 x - 2

w^{2} - 8 w + 7 = - 3

x^{2} - 13 x - 11 = - 7 x + 5

6 x^{2} + 19 x + 10 = 0

What are the solutions to the equation n^2-2n=15 ?
The solutions to the equation n^2-2n=15 are n=5,n=-3
Find the zeros of n^2-2n=15
The zeros of n^2-2n=15 are n=5,n=-3