What are the solutions to the equation x^2+2x-99=0 ?

The solutions to the equation x^2+2x-99=0 are x=9,x=-11

Find the zeros of x^2+2x-99=0

The zeros of x^2+2x-99=0 are x=9,x=-11

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x^{2} + 2 x - 99 = 0

x = 9, x = - 11

Solution steps

x^{2} + 2 x - 99 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 99 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 99) = 20

x_{1, 2} = \frac{- 2 \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 20}{2 \cdot 1}, x_{2} = \frac{- 2 - 20}{2 \cdot 1}

x = \frac{- 2 + 20}{2 \cdot 1} : 9

x = \frac{- 2 - 20}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = 9, x = - 11

4 x^{3} + 16 x^{2} - 25 x - 100

0 = 3 x^{2} + 12 x + 12

15 x^{2} - 35 x - 30

4 x^{2} - 16 x + 10 = 0

\frac{x ^{3}}{x ^{2}}

What are the solutions to the equation x^2+2x-99=0 ?
The solutions to the equation x^2+2x-99=0 are x=9,x=-11
Find the zeros of x^2+2x-99=0
The zeros of x^2+2x-99=0 are x=9,x=-11