What are the solutions to the equation a^2-5a+6=0 ?

The solutions to the equation a^2-5a+6=0 are a=3,a=2

Find the zeros of a^2-5a+6=0

The zeros of a^2-5a+6=0 are a=3,a=2

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a^{2} - 5 a + 6 = 0

a = 3, a = 2

Solution steps

a^{2} - 5 a + 6 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 6 = 1

a_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 1}, a_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 1}

a = \frac{- ( - 5 ) + 1}{2 \cdot 1} : 3

a = \frac{- ( - 5 ) - 1}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

a = 3, a = 2

3 x^{2} - 40 x + 100 = 0

x^{2} + x - 1

x^{2} - 24 x

x^{2} - 12 x = 85

x^{2} - 12 x + 32 = 4

What are the solutions to the equation a^2-5a+6=0 ?
The solutions to the equation a^2-5a+6=0 are a=3,a=2
Find the zeros of a^2-5a+6=0
The zeros of a^2-5a+6=0 are a=3,a=2