What are the solutions to the equation 8x^2-5x+1=0 ?

The solutions to the equation 8x^2-5x+1=0 are x= 5/16+i(sqrt(7))/(16),x= 5/16-i(sqrt(7))/(16)

Find the zeros of 8x^2-5x+1=0

The zeros of 8x^2-5x+1=0 are x= 5/16+i(sqrt(7))/(16),x= 5/16-i(sqrt(7))/(16)

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8 x^{2} - 5 x + 1 = 0

x = \frac{5}{16} + i \frac{7}{16}, x = \frac{5}{16} - i \frac{7}{16}

Solution steps

8 x^{2} - 5 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 8 \cdot 1}{2 \cdot 8}

Simplify

(- 5)^{2} - 4 \cdot 8 \cdot 1 : 7 i

x_{1, 2} = \frac{- ( - 5 ) \pm 7 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7 i}{2 \cdot 8}, x_{2} = \frac{- ( - 5 ) - 7 i}{2 \cdot 8}

x = \frac{- ( - 5 ) + 7 i}{2 \cdot 8} : \frac{5}{16} + i \frac{7}{16}

x = \frac{- ( - 5 ) - 7 i}{2 \cdot 8} : \frac{5}{16} - i \frac{7}{16}

The solutions to the quadratic equation are:

x = \frac{5}{16} + i \frac{7}{16}, x = \frac{5}{16} - i \frac{7}{16}

x^{2} + 8 x = - 28

x, x^{2} + x y + y^{2} = 1

s^{2} = 144

(3 x + 1)^{2} = 9

x^{2} + 245 = 0

What are the solutions to the equation 8x^2-5x+1=0 ?
The solutions to the equation 8x^2-5x+1=0 are x= 5/16+i(sqrt(7))/(16),x= 5/16-i(sqrt(7))/(16)
Find the zeros of 8x^2-5x+1=0
The zeros of 8x^2-5x+1=0 are x= 5/16+i(sqrt(7))/(16),x= 5/16-i(sqrt(7))/(16)