What are the solutions to the equation x^2-12x+36=44 ?

The solutions to the equation x^2-12x+36=44 are x=2(3+sqrt(11)),x=2(3-sqrt(11))

Find the zeros of x^2-12x+36=44

The zeros of x^2-12x+36=44 are x=2(3+sqrt(11)),x=2(3-sqrt(11))

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x^{2} - 12 x + 36 = 44

x = 2 (3 + 11), x = 2 (3 - 11)

Decimal Notation

x = 12.63324 \dots, x = - 0.63324 \dots

Solution steps

x^{2} - 12 x + 36 = 44

Move

44

to the left side

x^{2} - 12 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 8) = 411

x_{1, 2} = \frac{- ( - 12 ) \pm 4 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 11}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 4 11}{2 \cdot 1}

x = \frac{- ( - 12 ) + 4 11}{2 \cdot 1} : 2 (3 + 11)

x = \frac{- ( - 12 ) - 4 11}{2 \cdot 1} : 2 (3 - 11)

The solutions to the quadratic equation are:

x = 2 (3 + 11), x = 2 (3 - 11)

5 x^{2} + 9 x + 4

x^{2} - x + 30 = 0

4 x^{2} - 121 = 0

x^{2} - 4 x + 3

2 (x + 5)^{2} + 37 = 39

What are the solutions to the equation x^2-12x+36=44 ?
The solutions to the equation x^2-12x+36=44 are x=2(3+sqrt(11)),x=2(3-sqrt(11))
Find the zeros of x^2-12x+36=44
The zeros of x^2-12x+36=44 are x=2(3+sqrt(11)),x=2(3-sqrt(11))