What are the solutions to the equation 4x^2-12x-9=0 ?

The solutions to the equation 4x^2-12x-9=0 are x=(3(1+sqrt(2)))/2 ,x=(3(1-sqrt(2)))/2

Find the zeros of 4x^2-12x-9=0

The zeros of 4x^2-12x-9=0 are x=(3(1+sqrt(2)))/2 ,x=(3(1-sqrt(2)))/2

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4 x^{2} - 12 x - 9 = 0

x = \frac{3 ( 1 + 2 )}{2}, x = \frac{3 ( 1 - 2 )}{2}

Decimal Notation

x = 3.62132 \dots, x = - 0.62132 \dots

Solution steps

4 x^{2} - 12 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 ( - 9 )}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 (- 9) = 122

x_{1, 2} = \frac{- ( - 12 ) \pm 12 2}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 12 2}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 12 2}{2 \cdot 4}

x = \frac{- ( - 12 ) + 12 2}{2 \cdot 4} : \frac{3 ( 1 + 2 )}{2}

x = \frac{- ( - 12 ) - 12 2}{2 \cdot 4} : \frac{3 ( 1 - 2 )}{2}

The solutions to the quadratic equation are:

x = \frac{3 ( 1 + 2 )}{2}, x = \frac{3 ( 1 - 2 )}{2}

7 x^{2} - 3 x - 4 = 0

2 x^{2} - 4 x - 16 = 0

(x - 4)^{2} = - 49

x^{2} = 3 x - 10

- 0.002 x^{2} + 0.37 x - 8 = 0

What are the solutions to the equation 4x^2-12x-9=0 ?
The solutions to the equation 4x^2-12x-9=0 are x=(3(1+sqrt(2)))/2 ,x=(3(1-sqrt(2)))/2
Find the zeros of 4x^2-12x-9=0
The zeros of 4x^2-12x-9=0 are x=(3(1+sqrt(2)))/2 ,x=(3(1-sqrt(2)))/2