What are the solutions to the equation 3a^2+16a+17=0 ?

The solutions to the equation 3a^2+16a+17=0 are a=(-8+sqrt(13))/3 ,a=-(8+sqrt(13))/3

Find the zeros of 3a^2+16a+17=0

The zeros of 3a^2+16a+17=0 are a=(-8+sqrt(13))/3 ,a=-(8+sqrt(13))/3

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3 a^{2} + 16 a + 17 = 0

a = \frac{- 8 + 13}{3}, a = - \frac{8 + 13}{3}

Decimal Notation

a = - 1.46481 \dots, a = - 3.86851 \dots

Solution steps

3 a^{2} + 16 a + 17 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 3 \cdot 17}{2 \cdot 3}

1 6^{2} - 4 \cdot 3 \cdot 17 = 213

a_{1, 2} = \frac{- 16 \pm 2 13}{2 \cdot 3}

Separate the solutions

a_{1} = \frac{- 16 + 2 13}{2 \cdot 3}, a_{2} = \frac{- 16 - 2 13}{2 \cdot 3}

a = \frac{- 16 + 2 13}{2 \cdot 3} : \frac{- 8 + 13}{3}

a = \frac{- 16 - 2 13}{2 \cdot 3} : - \frac{8 + 13}{3}

The solutions to the quadratic equation are:

a = \frac{- 8 + 13}{3}, a = - \frac{8 + 13}{3}

2 x^{2} + 2 a^{2} b^{2} = 5 ab x

3 (x + 1) - x (5 x + 2) = 7

z^{2} - 2 z + 1 = 0

6 x - 6 x^{2} = 0

9 x^{2} - 12 x + 12 = 0

What are the solutions to the equation 3a^2+16a+17=0 ?
The solutions to the equation 3a^2+16a+17=0 are a=(-8+sqrt(13))/3 ,a=-(8+sqrt(13))/3
Find the zeros of 3a^2+16a+17=0
The zeros of 3a^2+16a+17=0 are a=(-8+sqrt(13))/3 ,a=-(8+sqrt(13))/3