What are the solutions to the equation x^2+18x+65=0 ?

The solutions to the equation x^2+18x+65=0 are x=-5,x=-13

Find the zeros of x^2+18x+65=0

The zeros of x^2+18x+65=0 are x=-5,x=-13

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x^{2} + 18 x + 65 = 0

x = - 5, x = - 13

Solution steps

x^{2} + 18 x + 65 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 65}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 65 = 8

x_{1, 2} = \frac{- 18 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 8}{2 \cdot 1}, x_{2} = \frac{- 18 - 8}{2 \cdot 1}

x = \frac{- 18 + 8}{2 \cdot 1} : - 5

x = \frac{- 18 - 8}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = - 5, x = - 13

y^{2} = 8 y

x, x^{2} + x y + y = x - 4

p^{2} - 2 p - 7 = 0

6 x^{2} - 42 x + 72 = 0

x^{2} + 24 x

What are the solutions to the equation x^2+18x+65=0 ?
The solutions to the equation x^2+18x+65=0 are x=-5,x=-13
Find the zeros of x^2+18x+65=0
The zeros of x^2+18x+65=0 are x=-5,x=-13