What are the solutions to the equation -5x^2+12x=-6 ?

The solutions to the equation -5x^2+12x=-6 are x=-(-6+sqrt(66))/5 ,x=(6+sqrt(66))/5

Find the zeros of -5x^2+12x=-6

The zeros of -5x^2+12x=-6 are x=-(-6+sqrt(66))/5 ,x=(6+sqrt(66))/5

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- 5 x^{2} + 12 x = - 6

x = - \frac{- 6 + 66}{5}, x = \frac{6 + 66}{5}

Decimal Notation

x = - 0.42480 \dots, x = 2.82480 \dots

Solution steps

- 5 x^{2} + 12 x = - 6

Move

6

to the left side

- 5 x^{2} + 12 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 5 ) \cdot 6}{2 ( - 5 )}

1 2^{2} - 4 (- 5) \cdot 6 = 266

x_{1, 2} = \frac{- 12 \pm 2 66}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 12 + 2 66}{2 ( - 5 )}, x_{2} = \frac{- 12 - 2 66}{2 ( - 5 )}

x = \frac{- 12 + 2 66}{2 ( - 5 )} : - \frac{- 6 + 66}{5}

x = \frac{- 12 - 2 66}{2 ( - 5 )} : \frac{6 + 66}{5}

The solutions to the quadratic equation are:

x = - \frac{- 6 + 66}{5}, x = \frac{6 + 66}{5}

x (3 x - 6) - 4 + 9 (x - 1) = 5

x^{2} - 10 x + 25 = 0

5 d^{2} + 6 d + 1 = 4 d^{2}

3 x^{2} - 4 = 140

3 x^{2} - 10 = 38

What are the solutions to the equation -5x^2+12x=-6 ?
The solutions to the equation -5x^2+12x=-6 are x=-(-6+sqrt(66))/5 ,x=(6+sqrt(66))/5
Find the zeros of -5x^2+12x=-6
The zeros of -5x^2+12x=-6 are x=-(-6+sqrt(66))/5 ,x=(6+sqrt(66))/5