What are the solutions to the equation solvefor x,y=(x-h)^2+k ?

The solutions to the equation solvefor x,y=(x-h)^2+k are x=sqrt(y-k)+h,x=-sqrt(y-k)+h

Find the zeros of solvefor x,y=(x-h)^2+k

The zeros of solvefor x,y=(x-h)^2+k are x=sqrt(y-k)+h,x=-sqrt(y-k)+h

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solve for

x, y = (x - h)^{2} + k

x = y - k + h, x = - y - k + h

Solution steps

y = (x - h)^{2} + k

Switch sides

(x - h)^{2} + k = y

Move

k

to the right side

(x - h)^{2} = y - k

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - h = y - k : x = y - k + h

Solve

x - h = - y - k : x = - y - k + h

The solutions to the quadratic equation are:

x = y - k + h, x = - y - k + h

- 0.0002037 x^{2} + 0.0170086 x - 0.06426 = 0

3 x^{2} + b x + 3 = 0

- 3 x^{2} - 18 x + 81 = 0

- 101 = - 3 x^{2} - 5

x (1 - 3 x) = 2 x - 1

What are the solutions to the equation solvefor x,y=(x-h)^2+k ?
The solutions to the equation solvefor x,y=(x-h)^2+k are x=sqrt(y-k)+h,x=-sqrt(y-k)+h
Find the zeros of solvefor x,y=(x-h)^2+k
The zeros of solvefor x,y=(x-h)^2+k are x=sqrt(y-k)+h,x=-sqrt(y-k)+h